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authordan miller2007-10-20 02:49:29 +0000
committerdan miller2007-10-20 02:49:29 +0000
commite36d23a85ebff914d74bb541558c2b6082b78edb (patch)
tree54b58fdf162e78af64055282a6035c8d2443389d /libraries/sqlite/unix/sqlite-3.5.1/test/subselect.test
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sqlite source (unix build) added to libraries
Diffstat (limited to 'libraries/sqlite/unix/sqlite-3.5.1/test/subselect.test')
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1# 2001 September 15
2#
3# The author disclaims copyright to this source code. In place of
4# a legal notice, here is a blessing:
5#
6# May you do good and not evil.
7# May you find forgiveness for yourself and forgive others.
8# May you share freely, never taking more than you give.
9#
10#***********************************************************************
11# This file implements regression tests for SQLite library. The
12# focus of this file is testing SELECT statements that are part of
13# expressions.
14#
15# $Id: subselect.test,v 1.14 2007/04/12 03:54:39 drh Exp $
16
17set testdir [file dirname $argv0]
18source $testdir/tester.tcl
19
20# Omit this whole file if the library is build without subquery support.
21ifcapable !subquery {
22 finish_test
23 return
24}
25
26# Basic sanity checking. Try a simple subselect.
27#
28do_test subselect-1.1 {
29 execsql {
30 CREATE TABLE t1(a int, b int);
31 INSERT INTO t1 VALUES(1,2);
32 INSERT INTO t1 VALUES(3,4);
33 INSERT INTO t1 VALUES(5,6);
34 }
35 execsql {SELECT * FROM t1 WHERE a = (SELECT count(*) FROM t1)}
36} {3 4}
37
38# Try a select with more than one result column.
39#
40do_test subselect-1.2 {
41 set v [catch {execsql {SELECT * FROM t1 WHERE a = (SELECT * FROM t1)}} msg]
42 lappend v $msg
43} {1 {only a single result allowed for a SELECT that is part of an expression}}
44
45# A subselect without an aggregate.
46#
47do_test subselect-1.3a {
48 execsql {SELECT b from t1 where a = (SELECT a FROM t1 WHERE b=2)}
49} {2}
50do_test subselect-1.3b {
51 execsql {SELECT b from t1 where a = (SELECT a FROM t1 WHERE b=4)}
52} {4}
53do_test subselect-1.3c {
54 execsql {SELECT b from t1 where a = (SELECT a FROM t1 WHERE b=6)}
55} {6}
56do_test subselect-1.3c {
57 execsql {SELECT b from t1 where a = (SELECT a FROM t1 WHERE b=8)}
58} {}
59
60# What if the subselect doesn't return any value. We should get
61# NULL as the result. Check it out.
62#
63do_test subselect-1.4 {
64 execsql {SELECT b from t1 where a = coalesce((SELECT a FROM t1 WHERE b=5),1)}
65} {2}
66
67# Try multiple subselects within a single expression.
68#
69do_test subselect-1.5 {
70 execsql {
71 CREATE TABLE t2(x int, y int);
72 INSERT INTO t2 VALUES(1,2);
73 INSERT INTO t2 VALUES(2,4);
74 INSERT INTO t2 VALUES(3,8);
75 INSERT INTO t2 VALUES(4,16);
76 }
77 execsql {
78 SELECT y from t2
79 WHERE x = (SELECT sum(b) FROM t1 where a notnull) - (SELECT sum(a) FROM t1)
80 }
81} {8}
82
83# Try something useful. Delete every entry from t2 where the
84# x value is less than half of the maximum.
85#
86do_test subselect-1.6 {
87 execsql {DELETE FROM t2 WHERE x < 0.5*(SELECT max(x) FROM t2)}
88 execsql {SELECT x FROM t2 ORDER BY x}
89} {2 3 4}
90
91# Make sure sorting works for SELECTs there used as a scalar expression.
92#
93do_test subselect-2.1 {
94 execsql {
95 SELECT (SELECT a FROM t1 ORDER BY a), (SELECT a FROM t1 ORDER BY a DESC)
96 }
97} {1 5}
98do_test subselect-2.2 {
99 execsql {
100 SELECT 1 IN (SELECT a FROM t1 ORDER BY a);
101 }
102} {1}
103do_test subselect-2.3 {
104 execsql {
105 SELECT 2 IN (SELECT a FROM t1 ORDER BY a DESC);
106 }
107} {0}
108
109# Verify that the ORDER BY clause is honored in a subquery.
110#
111ifcapable compound {
112do_test subselect-3.1 {
113 execsql {
114 CREATE TABLE t3(x int);
115 INSERT INTO t3 SELECT a FROM t1 UNION ALL SELECT b FROM t1;
116 SELECT * FROM t3 ORDER BY x;
117 }
118} {1 2 3 4 5 6}
119} ;# ifcapable compound
120ifcapable !compound {
121do_test subselect-3.1 {
122 execsql {
123 CREATE TABLE t3(x int);
124 INSERT INTO t3 SELECT a FROM t1;
125 INSERT INTO t3 SELECT b FROM t1;
126 SELECT * FROM t3 ORDER BY x;
127 }
128} {1 2 3 4 5 6}
129} ;# ifcapable !compound
130
131do_test subselect-3.2 {
132 execsql {
133 SELECT sum(x) FROM (SELECT x FROM t3 ORDER BY x LIMIT 2);
134 }
135} {3}
136do_test subselect-3.3 {
137 execsql {
138 SELECT sum(x) FROM (SELECT x FROM t3 ORDER BY x DESC LIMIT 2);
139 }
140} {11}
141do_test subselect-3.4 {
142 execsql {
143 SELECT (SELECT x FROM t3 ORDER BY x);
144 }
145} {1}
146do_test subselect-3.5 {
147 execsql {
148 SELECT (SELECT x FROM t3 ORDER BY x DESC);
149 }
150} {6}
151do_test subselect-3.6 {
152 execsql {
153 SELECT (SELECT x FROM t3 ORDER BY x LIMIT 1);
154 }
155} {1}
156do_test subselect-3.7 {
157 execsql {
158 SELECT (SELECT x FROM t3 ORDER BY x DESC LIMIT 1);
159 }
160} {6}
161do_test subselect-3.8 {
162 execsql {
163 SELECT (SELECT x FROM t3 ORDER BY x LIMIT 1 OFFSET 2);
164 }
165} {3}
166do_test subselect-3.9 {
167 execsql {
168 SELECT (SELECT x FROM t3 ORDER BY x DESC LIMIT 1 OFFSET 2);
169 }
170} {4}
171do_test subselect-3.10 {
172 execsql {
173 SELECT x FROM t3 WHERE x IN
174 (SELECT x FROM t3 ORDER BY x DESC LIMIT 1 OFFSET 2);
175 }
176} {4}
177
178# Ticket #2295.
179# Make sure type affinities work correctly on subqueries with
180# an ORDER BY clause.
181#
182do_test subselect-4.1 {
183 execsql {
184 CREATE TABLE t4(a TEXT, b TEXT);
185 INSERT INTO t4 VALUES('a','1');
186 INSERT INTO t4 VALUES('b','2');
187 INSERT INTO t4 VALUES('c','3');
188 SELECT a FROM t4 WHERE b IN (SELECT b FROM t4 ORDER BY b);
189 }
190} {a b c}
191do_test subselect-4.2 {
192 execsql {
193 SELECT a FROM t4 WHERE b IN (SELECT b FROM t4 ORDER BY b LIMIT 1);
194 }
195} {a}
196do_test subselect-4.3 {
197 execsql {
198 SELECT a FROM t4 WHERE b IN (SELECT b FROM t4 ORDER BY b DESC LIMIT 1);
199 }
200} {c}
201
202finish_test